Remaining limitation: how far can one gradient be extrapolated?
Useful step length depends on how that gradient changes with \(x\).
Use \(U(x)=-\log p(x)\). Around the MAP point:
\[
x_{\mathrm{MAP}}
:=
\underset{x}{\operatorname{arg\,max}}\,p(x)
=
\underset{x}{\operatorname{arg\,min}}\,U(x),
\qquad
\nabla U(x_{\mathrm{MAP}})=0.
\]
The simplest local model: gradient is linear in \(\delta x\) with slope 1 (unit local scale).
\[
\begin{gathered}
\delta x=x-x_{\mathrm{MAP}},\\
\nabla U(x_{\mathrm{MAP}}+\delta x)
\approx
\delta x.
\end{gathered}
\]
This is the Taylor / Gaussian local model.
Local Quadratic
Potential:
\[
U(x)=-\log(p(x)).
\]
MAP point / minimum:
\[
x_{\mathrm{MAP}}
=
\underset{x}{\operatorname{arg\,max}}\,p(x)
=
\underset{x}{\operatorname{arg\,min}}\,U(x).
\]
\[
\nabla U(x_{\mathrm{MAP}})=0,
\qquad
\delta x=x-x_{\mathrm{MAP}}.
\]
Unit local scale:
\[
\nabla U(x_{\mathrm{MAP}}+\delta x)
\approx
\delta x.
\]
Taylor at a minimum:
\[
U(x_{\mathrm{MAP}}+\delta x)
\approx
U(x_{\mathrm{MAP}})
+
\frac12\|\delta x\|^2.
\]
Local Gaussian:
\[
p_{\mathrm{loc}}(\delta x)
\propto
\exp\!\left(-\frac12\|\delta x\|^2\right).
\]
Why This Model?
If \(\nabla U\) changes like \(\delta x\), the measured gradient stays predictive over a local step.
Easy case for:
- Newton, Gauss–Newton, BFGS
- trust-region, Laplace, Fisher geometry