For each position \(x\), we add the same momentum distribution \(\varphi_M(m)\), because the Markov kernel depends on \(x\) and \(m\) now:
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That means it can be factorized:
\[
\pi_{\mathrm{aug}}(x,m)=\pi(x)\,\varphi_M(m).
\]
The \(x\)-marginal is unchanged:
\[
\int \pi_{\mathrm{aug}}(x,m)\,dm=\pi(x).
\]
The chain may move in \((x,m)\); summaries/sample results still use only \(x\).
Marginal Proof
Normalize the added variable:
\[
\int \varphi_M(m)\,dm=1.
\]
Then:
\[
\int \pi_{\mathrm{aug}}(x,m)\,dm
=
\pi(x)\int\varphi_M(m)\,dm
=
\pi(x).
\]
Therefore, for any function of \(x\):
\[
\mathbb E_\pi[f(x)]
=
\mathbb E_{\pi_{\mathrm{aug}}}[f(x)].
\]
Momentum can be refreshed independently because it is not part of the requested marginal.
\[
m\sim \varphi_M
\quad\text{given }x.
\]